endian: Fix bebitenc() to actually encode big-endian

bebitenc() just runs a downward loop over the same body as lebitenc().
That doesn't give you a byte-swapped result, it gives you the same final
value, just starting from the other side to fill it in. (Also, it
confused i++ and i--, so it really gives you a compiler error.)

The correct code needs to have the array index inverted relative to the
bit shift index to produce a big endian result.

Change-Id: I5c2da3a196334844ce23468bd0124bbe2f378c46
Signed-off-by: Julius Werner <jwerner@chromium.org>
Reviewed-on: https://review.coreboot.org/22322
Tested-by: build bot (Jenkins) <no-reply@coreboot.org>
Reviewed-by: Aaron Durbin <adurbin@chromium.org>

0 files changed, 0 insertions, 0 deletions